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`(pi)/3``(pi)/6``(2pi)/3``(pi)/2`

Transcript

Time | Transcript |
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00:00 - 00:59 | this question given that in a triangle ABC if a + b + b square into a plus b minus C is equal to a b then the measure of angle C is given by to start this question by writing requesting it was a + b + c into a plus b minus C is equal to a we love we know that a + b x this equation will get a + b whole square minus C square a + b into a Mi go to a square similar to the same property here which is equal to heavy solving open the bracket will get a square + b square + 2 AV minus is equal to a b ok enough for the following will get a square + b square minus b square is equal to minus A P ok this equation first |

01:00 - 01:59 | review of to find the value of cos 30 the value of cos is given by a square + b square minus C square divided by 2 AV Navi note value of a square + b square c square - 8 x 8 - A / 28 visible casset AV America at minus half its value of Cos is equal to minus 1 by 2 which will give angle C is equal to 2.3 has courses human Management by two value courses at what angle 2583 therefore we can stay at an angle C is equal to 5 by 3 which is the answer |

**Sine formula proof :Sine Rule**

**Problem on sine rule Type:-1(i) In a `DeltaABC` ; If `a=2;b=3 and sinA=2/3` ;find `/_B` (ii) In a `DeltaABC`; the angle of a triangle are in AP ; It is being given that `b:c=sqrt3:sqrt2`**

**An object is observed from three points `A, B,C` in the same horizontal line passing through the base of the object. The angle of elevation at `B` is twice and at `C` is thrice than that at `A`. If `AB=a, BC=b` prove that the height of the object is `h=(a/(2b))sqrt((a+b)(3b-a))` **

**The law of cosines proof :**

**In `Delta ABC` prove that (i)`a=bcosC+c cosB` (ii)` b=c cosA+acosC` (iii) `c=acosB+bcosA`**

**Half Angle Formula of `sin (A/2) ,Sin (B/2) ,sin(C/2)`**

**Half Angle Formula of `cos (A/2) ,cos (B/2), cos (C/2)`**

**Half Angle Formula of `tan(A/2), tan (B/2), tan (C/2)`**

**In any `DeltaABC` (i)`tan((B-C)/2)=((b-c)/(b+c))cot(A/2)` (ii) `tan((A-B)/2)=((a-b)/(a+b))cot(C/2)` (iii)`tan((C-A)/2)=((c-a)/(c+a))cot(B/2)`**

**Verify area of triangle is (i) `1/2 bc sin A` (ii) Herons Formula**